Files
hunjing/backend/app/ai_provider/routing/permissions.py
T
2026-08-21 16:00:13 +08:00

101 lines
3.4 KiB
Python

from __future__ import annotations
import fnmatch
from typing import Any
class PermissionRule:
"""模型能力访问控制的单条权限规则。
规则使用 ``fnmatch`` 风格的通配符模式匹配模型名称。
参数:
model_pattern: ``fnmatch`` 模式,用于匹配模型名(如 ``"deepseek-*"``)。
capability: 此规则管控的能力(如 ``"vision"``)。
allowed: 能力是否允许(``True`` 允许,``False`` 拒绝)。
示例::
# 拒绝 "basic-*" 模型上的 vision 能力
PermissionRule(model_pattern="basic-*", capability="vision", allowed=False)
# 允许所有模型的 thinking 能力
PermissionRule(model_pattern="*", capability="thinking", allowed=True)
"""
def __init__(
self,
model_pattern: str,
capability: str,
allowed: bool = True,
) -> None:
self.model_pattern = model_pattern
self.capability = capability
self.allowed = allowed
def match(self, model_name: str) -> bool:
"""检查此规则是否适用于给定的模型名。"""
return fnmatch.fnmatch(model_name, self.model_pattern)
def __repr__(self) -> str:
verb = "ALLOW" if self.allowed else "DENY"
return f"PermissionRule({verb} {self.capability} on {self.model_pattern!r})"
def __eq__(self, other: Any) -> bool:
if not isinstance(other, PermissionRule):
return NotImplemented
return (
self.model_pattern == other.model_pattern
and self.capability == other.capability
and self.allowed == other.allowed
)
def __hash__(self) -> int:
return hash((self.model_pattern, self.capability, self.allowed))
class CapabilityPermissionController:
"""控制哪些模型允许哪些能力。
按顺序评估 :class:`PermissionRule` 列表。
**最后匹配的规则** 胜出(最具体的规则应放在较宽泛的规则之后)。
如果没有规则匹配某个模型/能力对,该能力**默认允许**。
用法::
controller = CapabilityPermissionController([
PermissionRule(model_pattern="*", capability="vision", allowed=False),
PermissionRule(model_pattern="vision-*", capability="vision", allowed=True),
])
controller.check("fast-model", "vision") # False
controller.check("vision-model", "vision") # True
"""
def __init__(self, rules: list[PermissionRule] | None = None) -> None:
self._rules = list(rules) if rules else []
def check(self, model_name: str, capability: str) -> bool:
"""检查 *capability* 是否在 *model_name* 上被允许。
返回 ``True`` 表示允许,``False`` 表示拒绝。
"""
result: bool | None = None
for rule in self._rules:
if rule.capability == capability and rule.match(model_name):
result = rule.allowed
# Default: allow if no rule matched
return result if result is not None else True
def is_allowed(self, model_name: str, capability: str) -> bool:
""":meth:`check` 的别名。"""
return self.check(model_name, capability)
def filter_capabilities(
self,
model_name: str,
capabilities: set[str],
) -> set[str]:
"""返回 *capabilities* 中在 *model_name* 上允许的子集。"""
return {c for c in capabilities if self.check(model_name, c)}